However, the max in limits.h can be given in hex format,
e.g. 0xffffffff rather than 4294967295. Note that since
hex format requires two extra chars "0x", it will not
be shorter than the equivalent decimal representation
unless the number has 40 or more bits.
OT: Why 40? I couldn't do better than solve
2 + log16(x) = log10(x), approx. 2^39.2