El jue, 04-10-2007 a las 14:14 +0200, Stefan Guggisberg escribió:
On 10/4/07, Paco Avila <pav...@git.es> wrote:
El mié, 03-10-2007 a las 14:02 +0200, Stefan Guggisberg escribió:
On 10/2/07, Paco Avila <pav...@git.es> wrote:
El mar, 02-10-2007 a las 15:07 +0200, Thomas Mueller escribió:
Hi,
Property.getLength():
Returns the length of the value of this property. Returns the length
in bytes if the value is a PropertyType.BINARY, otherwise it returns
the number of characters needed to display the value in its string
form. Returns -1 if the implementation cannot determine the length.
Does this not work, or did I misunderstand the problem?
I didn't notice the method :) Anyway, "Property.getLength()" is supposed
to be so fast as getting the size stored in special a property?
yes, in fact even faster ;)
Do you mean that "node.getProperty("jcr:data").getLength()" is faster
than "node.getProperty("my:size")?
no. i was saying that
property.getLenght();
is probably faster than
node.getProperty("my:size").getLong();
i.e. i was assuming that you'd already read the property.
if that's not the case just reading a LONG property
is certainly faster that reading a BINARY property.
not in my case, when I need to make repository statistics, and only need
to get the stored data size no the data itself.
Thanks for the tip anyway! :)
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13 messages in org.apache.jackrabbit.usersRe: Getting the size of binary node c...
