On Wed, 18 Feb 2009 15:21:28 +0100 IOhannes m zmoelnig <zmoe...@iem.at> wrote:

The vanilla one is correct. It is consistent with mathematical and common syntactical properties of other asymmetrical (non commutative) operators

subtract A - B the second operand is the amount subtracted from the first operand (minuend) and the inlet order reflects this.

divide A/B the second operand (divisor) is the second inlet position, the first operand (dividend) is the first inlet.

So, for exponentiation A^B the first operand (base) is the first inlet, and the second operand (exponent) is the second inlet.

It's also that the signal domain [pow~] is consistent with the existing and long established message domain [pow]

At the risk of causing offence, Cyclone [pow~] made a mistake ordering inlets and I don't think it's good to take the broken Microsoft approach of putting historical, backwards compatability above correctness and future simplicity of code.

(FWIW I personally had to change dozens of my own patches including those already documented in a textbook - the pain is worth the gain to do things right.)

a.