14 messages in com.mysql.lists.mysqlRe: Challenging query....| From | Sent On | Attachments |
|---|---|---|
| Jeff McKeon | 16 Oct 2003 07:20 | |
| Gabriel Ricard | 16 Oct 2003 08:39 | |
| Jeff McKeon | 16 Oct 2003 09:39 | |
| Jeff McKeon | 16 Oct 2003 09:41 | |
| Rory McKinley | 16 Oct 2003 09:44 | |
| Jeff McKeon | 16 Oct 2003 09:50 | |
| Rory McKinley | 16 Oct 2003 10:18 | |
| Diana Soares | 16 Oct 2003 10:40 | |
| Gabriel Ricard | 16 Oct 2003 10:46 | |
| Jeff McKeon | 16 Oct 2003 11:04 | |
| Gabriel Ricard | 16 Oct 2003 11:10 | |
| Jeff McKeon | 16 Oct 2003 11:18 | |
| Gabriel Ricard | 16 Oct 2003 11:45 | |
| Director General: NEFACOMP | 17 Oct 2003 01:08 |
| Subject: | Re: Challenging query....![]() |
|---|---|
| From: | Gabriel Ricard (ga...@imaxsales.net) |
| Date: | 10/16/2003 10:46:55 AM |
| List: | com.mysql.lists.mysql |
Or you could just do one simply query as I explained previously, retrieve the data in PHP, and group it by date rather than spending the same time in PHP generating a massive, inefficient query (and if you have a large number of customers, you won't generate a query larger than the maximum MySQL packet size, or incur any limits on the number of joins or aliases).
Do this query:
SELECT YEAR(TheDate) AS Year,MONTH(TheDate) AS Month,CustomerName,CustomerID,SUM(Revenue*Quantity) AS Revenue FROM rev GROUP BY Year, Month ORDER BY Year,Month,CustomerID
Then use this code:
$revenues = array();
foreach( $results as $result ) { $revenues[ $result['Year'] ][ $result['Month'] ][ $result['CustomerID'] ] = $result['Revenue']; }
The result will be a simple multi-dimensional array with a minimal SQL query and minimal application code.
- Gabriel
On Thursday, October 16, 2003, at 01:19 PM, Rory McKinley wrote:
Hi Jeff
OK, aliasing table is creating a copy of one table but calling it something different, so you compare a table to itself e.g.:
FROM revenue a, revenue b, revenue c COULD ALSO BE FROM revenue AS a, revenue AS b, revenue AS c
I am referencing revenue three times but have aliased it as a, b, and c to make sure that my predicate makes sense.
As for the loop, I can give you something off the top of my head in rough (very!) PHP , if you don't come right, I can sit down and do the code a little more detailed
For simplification purposes, I am going to assume that you can alias tables as numbers (e.g. 1, 2, 3 instead of a, b, c) but I suggest you check if this is possible - if you can't there is a work around that just requires a bit more thought....
//Assume you have an array that has all your client ids in
$client_id_array.
//Create base values based on the first id...
$select_base = "YEAR(1.date) AS year, MONTH(1.date) AS month,
SUM(1.revenue) AS cust1_rev"
$for_base = "FROM revenue 1"
$predicate_base = "WHERE 1.customer_id = ".$client_id_array[0]
//Now loop through and append additional items to each string for each instance of a client
//Start at 1 not zero as we already have accounted for the first id above
for($j=1; $j < count($client_id_array); $j++) { $select_base = $select_base.', SUM('.($j+1).') AS cust'.($j+1).'_rev';
$for_base = $for_base.', revenue '.($j+1);
$predicate_base = $predicate_base.' AND (YEAR('.($j+1).'.date) = YEAR(1.date) AND MONTH('.($j+1).'.date) =MONTH(1.date) AND '.($j+1).'.customer_id = '.$client_id_array[$j].')';
}
//Once your loop is done, put the parts together
$query = $select_base.$for_base.$predicate_base;
If you can't use numbers, you can use single letters, but that requires a little more work incrementing ASCII numbers and then converting to letters - also makes things way more complicated if you have more than 26 clients :) but still doable.
HTH
Rory McKinley Nebula Solutions +27 82 857 2391 ror...@nebula.co.za "There are 10 kinds of people in this world, those who understand binary and those who don't" (Unknown)
----- Original Message ----- From: "Jeff McKeon" <jmck...@telaurus.com> To: "Rory McKinley" <ror...@nebula.co.za>; <mys...@lists.mysql.com> Sent: Thursday, October 16, 2003 6:51 PM Subject: RE: Challenging query....
If you have a way to generate the query code dynamically (e.g. using a loop in C, PHP etc.), you can build a query using aliased tables :
SELECT YEAR(a.date) AS year, MONTH(a.date) AS month, SUM(a.revenue) AS cust1_rev, SUM(b.revenue) AS cust2_rev, SUM(c.revenue) AS cust3_rev FROM revenue a, revenue b, revenue c WHERE a.customer_id = 1 AND (YEAR(b.date) = YEAR(a.date) AND MONTH(b.date) = MONTH(a.date) AND b.customer_id = 2) AND (YEAR(c.date) = YEAR(c.date) AND MONTH(c.date) = MONTH(c.date) AND c.customer_id = 3) GROUP BY year, month
Ok, that looks promising as I'll be using PHP, but I'm a little fuzzy on the logic you've set. What are "aliased tables" and how would I define, use them in an loop?
Thanks,
Jeff
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