7 messages in com.googlegroups.sqlalchemy[sqlalchemy] Can't figure out the joi...
FromSent OnAttachments
Alexandre Conrad23 Jan 2008 07:25 
Michael Bayer23 Jan 2008 08:06 
Michael Bayer23 Jan 2008 08:54 
Michael Bayer23 Jan 2008 11:21 
Alexandre Conrad24 Jan 2008 11:55 
Michael Bayer24 Jan 2008 12:54 
Michael Bayer24 Jan 2008 13:50 
Subject:[sqlalchemy] Can't figure out the joins across many tables with select_from()
From:Alexandre Conrad (acon@magic.fr)
Date:01/23/2008 07:25:04 AM
List:com.googlegroups.sqlalchemy

Hello,

still working intensivly with joined table inheritance. I have troubles making a long join across many tables. I need to query players from "player_table" where on the other end, slots_hot.id == 'foo':

player_table = Table('players', meta, Column('id', Integer, primary_key=True), Column('description', Unicode(20)), Column('id_site', None, ForeignKey('sites.id'), nullable=False), )

site_table = Table('sites', meta, Column('id', Integer, primary_key=True), Column('name', Unicode(40), nullable=False, unique=True), Column('type', Unicode(8)), )

# inherits "site_table" site_client_table = Table('site_clients', meta, Column('id', None, ForeignKey('sites.id'), primary_key=True), Column('id_client', None, ForeignKey('clients.id')), )

playlist_table = Table('playlists', meta, Column('id', Integer, primary_key=True), Column('type', Unicode(8), nullable=False), Column('name', Unicode(30), nullable=False), Column('description', Unicode(40)), )

# inherits "playlist_table" playlist_site_table = Table('playlists_site', meta, Column('id', None, ForeignKey('playlists.id'), primary_key=True), Column('id_site', None, ForeignKey('site_clients.id')), )

hotlink_table = Table('hotlinks', meta, Column('id', Integer, primary_key=True), Column('id_playlist', None, ForeignKey('playlists_site.id')), Column('id_hotslot', None, ForeignKey('slots_hot.id')), )

slot_table = Table('slots', meta, Column('id', Integer, primary_key=True), Column('type', Unicode(8), nullable=False), Column('position', Integer, nullable=False), Column('match_all_options', Boolean, default=False, nullable=False), Column('id_slot', None, ForeignKey('slots.id')), )

# inherits "slot_table" hot_slot_table = Table('slots_hot', meta, Column('id', None, ForeignKey('slots.id'), primary_key=True), Column('name', Unicode(30)), )

I'm trying to build the query using model.Player.query.select_from(player_table.join(site_table.join(site_client_table)))... but then I'm getting this error when trying further .join(playlist_site_table):

Can't find any foreign key relationships between 'sites' and '_FromGrouping object'

Any idea how I could do this long join ?

Again, I tried using the clearer-to-read syntax:

model.Player.query.join(['site', 'playlists', 'hotlinks', 'hotslot']).filter(model.SlotHot.c.id=='foo').all()

but of course, as soon as I hit inherited relations, it fails, so I have to build using either only filters:

.filter(Foo.c.id==Bar.c.id_foo).filter(Bar.c.id==Baz.c.id_baz).filter(...)

which makes it a 3 liner long query, or using tables directly with select_from(), which Im trying to do now, as show above.

Regards,