|Fall In Love with Sage||Feb 5, 2009 11:11 am|
|David Joyner||Feb 5, 2009 11:28 am|
|Fall In Love with Sage||Feb 5, 2009 11:47 am|
|David Joyner||Feb 5, 2009 11:54 am|
|Fall In Love with Sage||Feb 5, 2009 12:09 pm|
|Marshall Hampton||Feb 6, 2009 2:41 am|
|Jason Grout||Feb 6, 2009 2:44 am|
|Marshall Hampton||Feb 6, 2009 3:31 am|
|Subject:||[sage-support] Re: How can you read a .txt/csv file in Sage?|
|From:||Marshall Hampton (hamp...@gmail.com)|
|Date:||Feb 6, 2009 2:41:58 am|
Sometimes its convenient to use the DATA directory, which will be packaged with the worksheet if you save it (as a .sws file). So for example you could copy the file to the DATA directory doing something like:
os.system('cp /full/path/to/list2.txt ' + DATA + 'list2.txt')
f = open(DATA + 'list2.txt')
should work, and would still work if you saved a worksheet copy and moved it to another computer.
I am tempted to open a ticket in trac for some sort of read_csv command, which might behave like the following (NOTE: this is just wishful thinking at this point):
data_list = read_csv('my_file.csv') # data_list would be a list of lists of row data, converted to numerical types if possible data_list = read_csv('my_file.csv', seperator = '\t') #split lines by a tab character instead data_list = read_csv('my_file.csv', fields = [int,int,string]) #perhaps useful to have more explicit field conversions
Does something like that already exist? Seems very common as a task. Of course its not that hard to do ad-hoc, but it would make things more user-friendly for lots of people I think.
On Feb 5, 10:10 pm, Fall In Love with Sage <cs.l...@gmail.com> wrote:
Thank you! It works now :)
On Feb 5, 9:54 pm, David Joyner <wdjo...@gmail.com> wrote:
On Thu, Feb 5, 2009 at 2:48 PM, Fall In Love with Sage
Thank you for your response!
The problem is now in the following codes: 1. f = open("list2.txt") l1 = f.readline() ls1 = l1.split(" ") l1
gives: Traceback (click to the left for traceback) ... IOError: [Errno 2] No such file or directory: 'list2.txt'
Similarly, the eval function, eval(ls1), in (1) and the following code (2) causes the previous error.
2. f = open('list2.txt') varList = [x.split(' // ') for x in f.readlines()]
I have the file list2.txt at SageRoot.
Does it help to give it the abs path?
f = open("/full/path/to/list2.txt")
On Feb 5, 9:28 pm, David Joyner <wdjo...@gmail.com> wrote:
Possibly I'm not understanding your English. Python can read in any text file, for example csv. So, the answer to your question seems to be in the thread you cited.
Also, if you want to know which directory Sageroot is, type SAGE_ROOT. For example:
sage: SAGE_ROOT '/home/wdj/sagefiles/sage-3.3.alpha1'
Hope this helps.
On Thu, Feb 5, 2009 at 2:11 PM, Fall In Love with Sage
My .txt/csv -file looks like in Vim: 1,4 2,5 3,6 I can have both filetypes. I am not sure, which one Sage supports.
Open two columns in Sage: - I know that the file needs be at Sageroot. My Sage is installed at ~/ apps/Sage in Mac. Where in ~/apps/Sage do I need to put the file?
This question is based on the following discussions: 1.http://groups.google.com/group/sage-support/browse_thread/thread/4600... 2.http://stackoverflow.com/questions/494116/how-can-you-move-a-list-fro...
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